Python Questions and Answers – Exception Handling – 2

Python Multiple Choice Questions & Answers (MCQs) focuses on “Exception Handling – 2”.

Q 1. The following Python code will result in an error if the input value is entered as -5.

assert False, ‘Spanish’
A. True
B. False

Show Answer

Answer:-A. True

Explanation

The code shown above results in an assertion error. The output of the code is: Traceback (most recent call last): File “”, line 1, in assert False, ‘Spanish’ AssertionError: Spanish Hence, this statement is true.

Q 2. What will be the output of the following Python code?

x=10
y=8
assert x>y, ‘X too small’
A. Assertion Error
B. 10 8
C. 108
D. No output

Show Answer

Answer:-D. No output

Explanation

The code shown above results in an error if and only if xy, there is no error. Since there is no print statement, hence there is no output.

Q 3. What will be the output of the following Python code?

#generator
def f(x):
yield x+1
g=f(8)
print(next(g))
A. 8
B. 9
C. 7
D. Error

Show Answer

Answer:-B. 9

Explanation

The code shown above returns the value of the expression x+1, since we have used to keyword yield. The value of x is 8. Hence the output of the code is 9.

Q 4. What will be the output of the following Python code?

def f(x):
yield x+1
print(“test”)
yield x+2
g=f(9)
A. Error
B. test
C. test
10
12
D. No output

Show Answer

Answer:-D. No output

Explanation

The code shown above will not yield any output. This is because when we try to yield 9, and there is no next(g), the iteration stops. Hence there is no output.

Q 5. What will be the output of the following Python code?

def f(x):
yield x+1
print(“test”)
yield x+2
g=f(10)
print(next(g))
print(next(g))
A. No output
B.11
test
12
C. 11
test
D. 11

Show Answer

Answer:-B.11 test 12

Explanation

The code shown above results in the output: 11 test 12 This is because we have used next(g) twice. Had we not used next, there would be no output.

Q 6. What will be the output of the following Python code?

def a():
try:
f(x, 4)
finally:
print(‘after f’)
print(‘after f?’)
a()
A. No output
B. after f?
C. error
D. after f

Show Answer

Answer:-C. error

Explanation

This code shown above will result in an error simply because ‘f’ is not defined. ‘try’ and ‘finally’ are keywords used in exception handling.

Q 7. What will be the output of the following Python code?

def f(x):
for i in range(5):
yield i
g=f(8)
print(list(g))
A. [0, 1, 2, 3, 4]
B. [1, 2, 3, 4, 5, 6, 7, 8]
C. [1, 2, 3, 4, 5]
D. [0, 1, 2, 3, 4, 5, 6, 7]

Show Answer

Answer:-A. [0, 1, 2, 3, 4]

Explanation

The output of the code shown above is a list containing whole numbers in the range (5). Hence the output of this code is: [0, 1, 2, 3, 4].

Q 8. The error displayed in the following Python code is?

import itertools
l1=(1, 2, 3)
l2=[4, 5, 6]
l=itertools.chain(l1, l2)
print(next(l1))
A. ‘list’ object is not iterator
B. ‘tuple’ object is not iterator
C. ‘list’ object is iterator
D. ‘tuple’ object is iterator

Show Answer

Answer:-B. ‘tuple’ object is not iterator

Explanation

The error raised in the code shown above is that: ‘tuple’ object is not iterator. Had we given l2 as argument to next, the error would have been: ‘list’ object is not iterator.

Q 9. Which of the following is not an exception handling keyword in Python?
A. try
B. except
C. accept
D. finally

Show Answer

Answer:-C. accept

Explanation

The keywords ‘try’, ‘except’ and ‘finally’ are exception handling keywords in python whereas the word ‘accept’ is not a keyword at all.

Q 10. What will be the output of the following Python code?

g = (i for i in range(5))
type(g)
A. class <’generator’>
B. class <‘iteration’>
C. class <’range’>
D. class <’loop’>

Show Answer

Answer:-A. class <’generator’>

Explanation

10. What will be the output of the following Python code? g = (i for i in range(5)) type(g) a) class <’loop’> b) class <‘iteration’> c) class <’range’> d) class <’generator’> View Answer Answer: d Explanation: Another way of creating a generator is to use parenthesis. Hence the output of the code shown above is: class<’generator’>.

Q 11. What’s the output of the following Python code?

Python

def div_by_zero(x, y):
    try:
        return x / y
    except ZeroDivisionError:
        print("Error: Can't divide by zero")
        return None

print(div_by_zero(10, 2))
print(div_by_zero(10, 0))

A. 5.0 Error: Can't divide by zero None

B. 5.0 Error: Can't divide by zero

C. 5.0 None Error: Can't divide by zero

D. Error: Can't divide by zero 5.0

Show Answer

A. 5.0 Error: Can’t divide by zero None

Explanation

The first call, div_by_zero(10, 2), executes the try block successfully and returns 5.0. The second call, div_by_zero(10, 0), triggers a ZeroDivisionError, which is caught by the except block. This block prints the error message “Error: Can’t divide by zero” and then returns None. The final two print statements in the code display the return values from the two function calls.

Q 12. Which of the following statements about Python’s try...except...finally block is true?

A. The finally block is only executed if an exception occurs.

B. The except block is always executed, even if no exception occurs.

C. The finally block always executes, regardless of whether an exception occurred or was handled.

D. The finally block is optional and is used to clean up resources, but it doesn’t run if an exception is raised.

Show Answer

C. The finally block always executes, regardless of whether an exception occurred or was handled.

Explanation

The finally block is guaranteed to execute. It’s used for cleanup actions like closing files or releasing network connections, ensuring these actions happen regardless of whether the code in the try block succeeds or fails.

Q 13. What does the else block in a try...except...else statement do?

A. It executes when an exception is handled by the except block.

B. It executes if the try block is executed without any exceptions.

C. It executes only when the finally block is not present.

D. It is a placeholder and has no functional purpose.

Show Answer

B. It executes if the try block is executed without any exceptions.

Explanation

The else block in a try…except statement is optional and runs only if the code in the try block executes successfully and no exception is raised. It’s often used to contain code that should run only after the try block’s success.

Q 14. What’s the output of the following code?

Python

try:
    print("Trying...")
    raise TypeError
except NameError:
    print("Caught NameError")
except TypeError:
    print("Caught TypeError")
finally:
    print("Finally!")

A. Trying... Caught NameError Finally!

B. Trying... Finally!

C .Trying... Caught TypeError Finally!

D .Trying... Caught TypeError

Show Answer

C .Trying… Caught TypeError Finally!

Explanation

The try block starts executing and prints “Trying…”. The raise TypeError statement immediately raises a TypeError exception. Python then looks for an except block that can handle this specific exception. It finds except TypeError, so it executes the code inside that block, printing “Caught TypeError”. After the exception is handled, the finally block is executed, printing “Finally!”.

Q 15. In Python, is it possible to have an except block without a specific exception name?

A. No, every except block must specify an exception.

B. Yes, except with no exception name catches all exceptions, but it’s generally considered bad practice.

C. Yes, except with no exception name is the preferred way to catch all exceptions.

D. No, this will cause a syntax error.

Show Answer

B. Yes, except with no exception name catches all exceptions, but it’s generally considered bad practice.

Explanation

You can have a bare except block without specifying an exception type. This will catch all exceptions that are raised. However, this is generally discouraged because it can hide programming errors and make debugging more difficult by catching unexpected exceptions. A better approach is to catch specific exceptions or use a general exception class like Exception as a fallback.